64+4x^2+(1/16)x^4

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Solution for 64+4x^2+(1/16)x^4 equation: 


x in (-oo:+oo)

(1/16)*x^4+4*x^2+64 = 0

1/16*x^4+4*x^2+64 = 0

t_1 = x^2

1/16*t_1^2+4*t_1^1+64 = 0

1/16*t_1^2+4*t_1+64 = 0

DELTA = 4^2-(1/16*4*64)

DELTA = 0

t_1 = -4/(1/16*2)

t_1 = -32 or t_1 = -32

t_1 = -32

x^2+32 = 0

1*x^2 = -32 // : 1

x^2 = -32

t_1 = -32

x^2+32 = 0

1*x^2 = -32 // : 1

x^2 = -32

x belongs to the empty set

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